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$$\frac{{\mathrm{d}}^2\mathbf{x}}{\mathrm{d}{t}^2}=-G\int {\mathrm{d}}^3{\mathbf{x}}^{\prime }\frac{\mathbf{x}-{\mathbf{x}}^{\prime }}{\left|\mathbf{x}-{\mathbf{x}}^{\prime }\right|}\rho \left({\mathbf{x}}^{\prime }\right)+{\mathbf{F}}_{\epsilon }$$

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since 2021-9-5