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$$ \frac{{{{\rm{d}}^2}{\bf{x}}}}{{{\rm{d}}{t^2}}} = - G\int {{{\rm{d}}^3}{\bf{x}}'\frac{{{\bf{x}} - {\bf{x}}'}}{{\left| {{\bf{x}} - {\bf{x}}'} \right|}}\rho \left( {{\bf{x}}'} \right)} + {{\bf{F}}_\varepsilon } $$



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